102. (a) The distance traveled in one revolution is 2πR= 2(4.6 m) = 29 m. The (constant) speed is consequently v= (29 m)/(30 s) = 0.96 m/s. (b) Newton’s second law (using Eq. 6-17 for the magnitude of the acceleration) leads to fmvRms=FHGIKJ=2020(. )
This is the end of the preview. Sign up
access the rest of the document.