ch06-p104 - 104. We note that FN = mg in this situation, so...

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104. We note that F N = mg in this situation, so f k = μ k mg = (0.32) (220 N) = 70.4 N and f s ,max = s mg = (0.41) (220 N) = 90.2 N. (a) The person needs to push at least as hard as the static friction maximum if he hopes to start it moving. Denoting his force as P , this means a value of P slightly larger than 90.2 N is sufficient. Rounding to two figures, we obtain
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