This preview shows page 1. Sign up to view the full content.
104. We note that
F
N
=
mg
in this situation, so
f
k
=
μ
k
mg
= (0.32) (220 N) = 70.4 N and
f
s
,max
=
s
mg
= (0.41) (220 N) = 90.2 N.
(a) The person needs to push at least as hard as the static friction maximum if he hopes to
start it moving. Denoting his force as
P
, this means a value of
P
slightly larger than
90.2 N is sufficient. Rounding to two figures, we obtain
This is the end of the preview. Sign up
to
access the rest of the document.
 Spring '08
 Any
 Physics, Force, Friction

Click to edit the document details