1. (a) The change in kinetic energy for the meteorite would be ()()22631411410kg1510m/s0J22fiiiiKK K KmvΔ= − =− =−=−××=−×,or14||510JKΔ=×. The negative sign indicates that kinetic energy is lost. (b) The energy loss in units of megatons of TNT would be 14151 megaton TNT5 10 J 0.1megaton TNT.
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