ch07-p009 - 9. Since this involves constant-acceleration...

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9. Since this involves constant-acceleration motion, we can apply the equations of Table 2-1, such as xv t a t =+ 0 1 2 2 (where x 0 0 = ). We choose to analyze the third and fifth points, obtaining 2 0 2 0 1 0.2m (1.0 s) (1.0 s) 2 1 0.8m (2.0 s) (2.0 s) 2 va Simultaneous solution of the equations leads to 0 0 v = and a = 040 .m s 2 . We now have two ways to finish the problem. One is to compute force from
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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