ch07-p011 - 11. We choose +x as the direction of motion (so...

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11. We choose + x as the direction of motion (so G a and G F are negative-valued). (a) Newton’s second law readily yields 2 (85kg)( 2.0m/s ) F =− G so that 2 ||1 . 71 0N FF ==× G . (b) From Eq. 2-16 (with v = 0) we have () 2 22 0 2 37m/s 02 3 . 4 1 0 m 2 2.0m/s va x x =+Δ ¡ Δ=− = × . Alternatively, this can be worked using the work-energy theorem. (c) Since G F is opposite to the direction of motion (so the angle φ between G F and G d x is 180°) then Eq. 7-7 gives the work done as 4 5.8 10 J WF x =− Δ =− × . (d) In this case, Newton’s second law yields
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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