ch07-p012 - 12 The change in kinetic energy can be written...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
22 11 () ( 2 ) fi Km v v m a x m a x Δ= − = Δ= Δ where we have used 2 vv a x =+Δ from Table 2-1. From Fig. 7-27, we see that (0 30) J 30 J K Δ=− = when 5 m x Δ=+ . The acceleration can then be obtained as 2 (3 0 J ) 0.75 m/s . (8.0 kg)(5.0 m) K a mx Δ− == = Δ The negative sign indicates that the mass is decelerating. From the figure, we also see that when 5 m x = the kinetic energy becomes zero, implying that the mass comes to rest
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online