ch07-p012 - 12. The change in kinetic energy can be written...

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22 11 () ( 2 ) fi Km v v m a x m a x Δ= − = Δ= Δ where we have used 2 vv a x =+Δ from Table 2-1. From Fig. 7-27, we see that (0 30) J 30 J K Δ=− = when 5 m x Δ=+ . The acceleration can then be obtained as 2 (3 0 J ) 0.75 m/s . (8.0 kg)(5.0 m) K a mx Δ− == = Δ The negative sign indicates that the mass is decelerating. From the figure, we also see that when 5 m x = the kinetic energy becomes zero, implying that the mass comes to rest
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