13. (a) The forces are constant, so the work done by any one of them is given by WFd=⋅GG, where Gdis the displacement. Force GF1is in the direction of the displacement, so111cos(5.00 N)(3.00m)cos015.0 J.dφ==°=ForceGF2makes an angle of 120° with the displacement, so 222cos(9.00 N)(3.00m)cos12013.5 J.d°=−ForceGF3is perpendicular to the displacement, so
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