(b) The force of gravity is in the same direction as the displacement, so it does work gWMgd=.(c) The total work done on the block is −+=344Mgd. Since the block starts from rest, we use Eq. 7-15 to conclude that this 4bgis the block’s kinetic energyKat the moment it has descended the distance d.(d) Since 212,KMv=the speed is vKMMgdMgd===2242(/)at the moment the block has descended the distance d.19. (a) We use Fto denote the magnitude of the force of the cord on the block. This force
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.