ch07-p022 - 22. From the figure, one may write the kinetic...

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22 0 2 2(40.0 J) 5.00 kg. (4.00 m/s) s K m v == = Thus, the normal force is 2 2 2 2 ( ) (5.0 kg) (9.8 m/s ) (20 N) 44.7 N 45 N. yx Fm g F =− = −= 22. From the figure, one may write the kinetic energy (in units of J) as a function of x as 20 40 20 s KK x x Since x WK F x =Δ = ⋅Δ G , the component of the force along the force along + x is /2 0 N . x Fd K d x The normal force on the block is
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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