ch07-p023 - direction of motion of the block). Thus, the...

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23. Eq. 7-15 applies, but the wording of the problem suggests that it is only necessary to examine the contribution from the rope (which would be the “ W a ” term in Eq. 7-15): W a = (50 N)(0.50 m) = 25 J (the minus sign arises from the fact that the pull from the rope is anti-parallel to the
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Unformatted text preview: direction of motion of the block). Thus, the kinetic energy would have been 25 J greater if the rope had not been attached (given the same displacement)....
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