24. We use
d
to denote the magnitude of the spelunker’s displacement during each stage.
The mass of the spelunker is
m
= 80.0 kg. The work done by the lifting force is denoted
W
i
where
i
= 1, 2, 3 for the three stages. We apply the workenergy theorem, Eq. 1715.
(a) For stage 1,
Wm
g
d K m
v
v
11
1
2
1
2
1
500
−==
=
Δ
,.
where
m / s. This gives
22
2
3
(80.0 kg)(9.80 m/s )(10.0 m)
(80.0 kg)(5.00 m/s)
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Force, Mass, Work, WorkEnergy Theorem

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