24. We use dto denote the magnitude of the spelunker’s displacement during each stage. The mass of the spelunker is m= 80.0 kg. The work done by the lifting force is denoted Wiwhere i= 1, 2, 3 for the three stages. We apply the work-energy theorem, Eq. 17-15. (a) For stage 1, Wmgd K mvv1112121500−===Δ,.where m / s. This gives 2223(80.0 kg)(9.80 m/s )(10.0 m)(80.0 kg)(5.00 m/s)
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.