ch07-p025 - 25. (a) The net upward force is given by F + FN...

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2 2 3.00 N (0.250 kg)(9.80 m/s ) 2.20 m/s 0.250 kg N Fm g m a a −= ¡ == . Thus the force from the cable is 4 ( )( ) 1.08 10 N N M a gF =+ +−= × , and the work done by the cable on the cab is 44 1 (1.80 10 N)(2.40 m) 2.59 10 J. WF d × = × (b) If 92.61 kJ W = and 2 10.5 m d = , the magnitude of the normal force is 4 2 2 9.261 10 J ( ) (0.250 kg 900 kg)(9.80 m/s ) 2.45 N. 10.5 m N W M g d × + = 25. (a) The net upward force is given by
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