32
2
1
(9.0 10 N/m)[(0.050 m)
( 0.050 m) ]
0 J.
2
s
W
=×
−
−
=
(d) Moving from
5.0 cm
i
x
=+
to
9.0 cm
x
=−
, we have
2
1
(9.0 10 N/m)[(0.050 m)
( 0.090 m) ]
25 J.
2
s
W
−
−
=
−
27. From Eq. 725, we see that the work done by the spring force is given by
22
1
()
2
s
if
Wk
x
x
.
The fact that 360 N of force must be applied to pull the block to
x
= + 4.0 cm implies that
the spring constant is
3
360 N
90 N/cm
9.0 10 N/m
4.0 cm
k
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force, Work

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