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45. (a) The power is given by
P
=
Fv
and the work done by
G
F
from time
t
1
to time
t
2
is
given by
WP
tF
v
t
t
t
t
t
d
d
==
z
z
.
1
2
1
2
Since
G
F
is the net force, the magnitude of the acceleration is
a
=
F
/
m
, and, since the
initial velocity is
v
0
0
=
, the velocity as a function of time is given by
vv a
t Fm
t
=+=
0
()
.
Thus
2
1
22
2
2
21
1
(/
)
d
)
(
)
.
2
t
t
WF
m
t
t
F
m
t
t
−
³
For
t
1
0
=
and
2
1.0s,
t
=
2
2
1 (5.0 N)
(1.0 s) = 0.83 J.
5
k
g
W
§·
=
¨¸
©¹
(b) For
1
t
=
and
2
2.0s,
t
=
2
1 (5.0 N)
[(2.0 s)
(1.0 s) ]
2.5 J.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Acceleration, Force, Power, Work

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