(c) With
y
=
h
= 5
R
, at
P
we find
22
5
5(3.20 10 kg)(9.80 m/s )(0.12 m)
0.19 J
Um
g
R
−
==×
=
.
(d) With
y
=
R
, at
Q
we have
(3.20 10 kg)(9.80 m/s )(0.12 m)
0.038 J
g
R
−
=
(e) With
y
= 2
R
, at the top of the loop, we find
2
2(3.20 10 kg)(9.80 m/s )(0.12 m)
0.075 J
g
R
−
=
(f) The new information
()
v
i
≠
0 is not involved in any of the preceding computations;
the above results are unchanged.
8. We use Eq. 712 for
W
g
and Eq. 89 for
U
.
(a) The displacement between the initial point and
Q
has a vertical component of
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 Spring '08
 Any
 Physics

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