ch08-p009 - 9. We neglect any work done by friction. We...

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9. We neglect any work done by friction. We work with SI units, so the speed is converted: v = 130(1000/3600) = 36.1 m/s. (a) We use Eq. 8-17: K f + U f = K i + U i with U i = 0, U f = mgh and K f = 0. Since Km v i = 1 2 2 , where v is the initial speed of the truck, we obtain 22 2 2 1 (36.1m/s) 66.5 m 2 2 2(9.8 m/s ) v mv mgh h g = ¡ == = . If L is the length of the ramp, then L sin 15° = 66.5 m so that L = (66.5 m)/sin 15° = 257
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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