11. (a) If Kiis the kinetic energy of the flake at the edge of the bowl, Kfis its kinetic energy at the bottom, Uiis the gravitational potential energy of the flake-Earth system with the flake at the top, and Ufis the gravitational potential energy with it at the bottom, thenKf+ Uf= Ki+ Ui.Taking the potential energy to be zero at the bottom of the bowl, then the potential energy at the top is Ui= mgrwhere r= 0.220 m is the radius of the bowl and mis the mass of the flake.Ki= 0 since the flake starts from rest. Since the problem asks for the speed at the
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.