h
v
g
=
°
=
0
2
sin 28
4.4 m
2
bg
.
(b) We see that all reference to mass cancels from the above computations, so a new
value for the mass will yield the same result as before.
24. From Chapter 4, we know the height
h
of the skier's jump can be found from
vv
g
h
yy
2
0
2
02
== −
where
v
0
y
=
v
0
sin 28° is the upward component of the skier's “launch
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy

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