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28. We take the original height of the box to be the
y
= 0 reference level and observe that,
in general, the height of the box (when the box has moved a distance
d
downhill) is
sin 40
yd
=−
°
.
(a) Using the conservation of energy, we have
K
U
K U
mv
mgy
kd
ii
+=
+
¡
+
+
00
1
2
1
2
22
.
Therefore, with
d
= 0.10 m, we obtain
v
= 0.81 m/s.
(b) We look for a value of
d
≠
0 such that
K
= 0.
KU KU
m
g
y k
d
+
¡
+=+
+
000
1
2
2
.
Thus, we obtain
mgd
kd
sin 40
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Conservation Of Energy, Energy

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