30. From the slope of the graph, we find the spring constant kFx===ΔΔ01010..NcmNm (a) Equating the potential energy of the compressed spring to the kinetic energy of the cork at the moment of release, we have 121222kxmvvxkm=¡=which yields v= 2.8 m/s for m= 0.0038 kg and
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.