ch08-p034 - 34. The distance the marble travels is...

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34. The distance the marble travels is determined by its initial speed (and the methods of Chapter 4), and the initial speed is determined (using energy conservation) by the original compression of the spring. We denote h as the height of the table, and x as the horizontal distance to the point where the marble lands. Then x = v 0 t and hg t = 1 2 2 (since the vertical component of the marble's “launch velocity” is zero). From these we find xv h g = 0 2 . We note from this that the distance to the landing point is directly proportional to the initial speed. We denote v 0 1 be the initial speed of the first shot and D 1 = (2.20 – 0.27) m = 1.93 m be the horizontal distance to its landing point; similarly, v 02 is the initial speed of the second shot and
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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