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36. Let
N
F
G
be the normal force of the ice on him and
m
is his mass. The net inward force
is
mg
cos
θ
–
F
N
and, according to Newton's second law, this must be equal to
mv
2
/
R
,
where
v
is the speed of the boy. At the point where the boy leaves the ice
F
N
= 0, so
g
cos
=
v
2
/
R
. We wish to find his speed. If the gravitational potential energy is taken to be
zero when he is at the top of the ice mound, then his potential energy at the time shown is
U
= –
mgR
(1 – cos
θ
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 Spring '08
 Any
 Physics, Force, Mass

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