ch08-p044 - 44. (a) The work is W = Fd = (35.0 N)(3.00 m) =...

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(c) Much of the work (105 J ) has been “wasted” due to the 70.6 J of thermal energy generated, but there still remains (105 – 70.6 ) J = 34.4 J which has gone into increasing the kinetic energy of the block. (It has not gone into increasing the potential energy of the block because the floor is presumed to be horizontal.)
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Unformatted text preview: 44. (a) The work is W = Fd = (35.0 N)(3.00 m) = 105 J. (b) The total amount of energy that has gone to thermal forms is (see Eq. 8-31 and Eq. 6-2) Δ E th = μ k mgd = (0.600)(4.00 kg)(9.80 m/s 2 )(3.00 m) = 70.6 J. If 40.0 J has gone to the block then (70.6 – 40.0) J = 30.6 J has gone to the floor....
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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