ch08-p058 - 58(a Using the force analysis shown in Chapter...

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Δ Ef d m g d kk th J == = ° = × μθ cos . . cos . . 010 267 61 20 15 10 2 bg b g (b) The potential energy change is Δ U = mg (– d sin θ ) = (267 N)(– 6.1 m) sin 20° = –5.6 × 10 2 J. The initial kinetic energy is 22 2 1 1 267 N (0.457m/s ) 2.8J. 9 . 8 m / s ii Km v §· = ¨¸ ©¹ Therefore, using Eq. 8-33 (with W = 0), the final kinetic energy is KK UE fi =− −× ΔΔ th J 2 8 56 10 15 10 41 10
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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