Δ
Ef
d
m
g
d
kk
th
J
==
=
°
=
×
μθ
cos
.
. cos
.
.
010 267 61
20
15 10
2
bg
b
g
(b) The potential energy change is
Δ
U
=
mg
(–
d
sin
θ
) = (267 N)(– 6.1 m) sin 20° = –5.6
×
10
2
J.
The initial kinetic energy is
22
2
1
1
267 N
(0.457m/s )
2.8J.
9
.
8
m
/
s
ii
Km
v
§·
=
¨¸
©¹
Therefore, using Eq. 833 (with
W
= 0), the final kinetic energy is
KK
UE
fi
=−
−
−×
=×
ΔΔ
th
J
2 8
56 10
15 10
41 10
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Force, Potential Energy

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