59. (a) With x= 0.075 m and k=320N m, Eq. 7-26 yields Wkxs=−122090. J.For later reference, this is equal to the negative of ΔU.(b) Analyzing forces, we find FN= mgwhich meanskkNkfFmgμμ==. With d= x, Eq. 8-31 yieldsΔEfdmgxthJ==μ( . )( . )( . )( .
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.