ch08-p059 - 1 59(a With x = 0.075 m and k = 320 N m Eq 7-26...

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59. (a) With x = 0.075 m and k = 320N m, Eq. 7-26 yields Wk x s =− 1 2 2 090 . J . For later reference, this is equal to the negative of Δ U . (b) Analyzing forces, we find F N = mg which means kk Nk f Fm g μμ == . With d = x , Eq. 8-31 yields Δ Ef d m g x th J = = μ ( . )( . )( . )( .
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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