59. (a) With
x
= 0.075 m and
k
=
320N m, Eq. 726 yields
Wk
x
s
=−
1
2
2
090
.
J
.
For
later reference, this is equal to the negative of
Δ
U
.
(b) Analyzing forces, we find
F
N
=
mg
which means
kk
Nk
f
Fm
g
μμ
==
. With
d
=
x
, Eq.
831 yields
Δ
Ef
d
m
g
x
th
J
=
=
μ
( . )( . )( . )( .
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Force

Click to edit the document details