ch08-p083 - K a mgy a 1 2 k(0.20 m 2 from which we obtain K...

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83. The initial height shown in the figure is the y = 0 level in our computations of U g , and in parts (a) and (b) the heights are y a = (0.80 m)sin 40 ° = 0.51 m and y b = (1.00 m) sin 40 ° = 0.64 m, respectively. (a) The conservation of energy, Eq. 8-17, leads to K i + U i = K a + U a ¡ 16 J + 0 =
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Unformatted text preview: K a + mgy a + 1 2 k (0.20 m) 2 from which we obtain K a = (16 – 5.0 – 4.0) J = 7.0 J. (b) Again we use the conservation of energy K i + U i = K b + U b ¡ K i + 0 = 0 + mgy b + 1 2 k (0.40 m) 2 from which we obtain K i = 6.0 J + 16 J = 22 J....
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