ch08-p100 - 100. (a) At the highest point, the velocity v =...

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100. (a) At the highest point, the velocity v = v x is purely horizontal and is equal to the horizontal component of the launch velocity (see section 4-6): v o x = v o cos θ , where 30 in this problem. Eq. 8-17 relates the kinetic energy at the highest point to the launch kinetic energy: K o = mg y + 1 2 mv 2 = 1 2 mv o x 2 + 1 2 mv o y 2 . with y = 1.83 m. Since the mv ox 2 /2 term on the left-hand side cancels the m v 2 /2 term on the right-hand side, this yields
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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