100. (a) At the highest point, the velocity v= vxis purely horizontal and is equal to the horizontal component of the launch velocity (see section 4-6): vox=vocosθ, where 30=°in this problem. Eq. 8-17 relates the kinetic energy at the highest point to the launch kinetic energy: Ko= mg y+ 12mv2= 12mvox2+ 12mvoy2.withy = 1.83 m. Since the mvox2/2 term on the left-hand side cancels the mv2/2 term on the right-hand side, this yields
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.