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m
Pt
vv
fi
=
−
=
×
−
=×
2
2 15 10
360
25
10
21 10
22
6
6
bg
ch
b
g
b
g
.
.
Ws
ms
kg.
(b) With
t
arbitrary, we use
Pt
m v
v
i
=−
1
2
to solve for the speed
v
=
v
(
t
) as a
function of time and obtain
vt
v
Pt
m
t
t
i
b g
b
g
b
g
=+
=
+
×
×
2
2
6
6
2
10
21
51
0
100 15
.
.
.
in SI units (
v
in m/s and
t
in s).
(c) The force
F
(
t
) as a function of time is
Ft
P
t
b g
b g
==
×
+
15 10
100 15
6
.
.
in SI units (
F
in N and
t
in s).
(d) The distance
d
the train moved is given by
360
1/2
3/2
360
3
00
0
34
3
( )
100
100
6.7 10 m.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy, Kinetic Energy, Mass, Work

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