KU K U fdmvmgyf dmvmgdmgdkkk0002021212+=+++=++=+toptopsincosθμθwhich — upon canceling the mass and rearranging — provides the result for d:dvgk=+=02215μθcossin.bgm. (c) The thermal energy generated by friction is fkd= μkmgdcos = 26 J. (d) The slide back down, from the height y= 1.5 sin 30°is also described by Eq. 8-33. With ΔEthagain equal to 26 J, we have KUfdmgymvktoptopbotbotbot+=++¡++0120262from which we find vbotms=21..106. We take the bottom of the incline to be the y= 0 reference level. The incline angle is 30=°. The distance along the incline
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.