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KU K U f
d
mv
mgy
f d
mv
mgd
mgd
k
k
k
00
0
2
0
2
1
2
1
2
+=
+
+
+=+
+
=+
top
top
sin
cos
θμ
θ
which — upon canceling the mass and rearranging — provides the result for
d
:
d
v
g
k
=
+
=
0
2
2
15
μθ
cos
sin
.
bg
m.
(c) The thermal energy generated by friction is
f
k
d
=
μ
k
mgd
cos
= 26 J.
(d) The slide back down, from the height
y
= 1.5 sin 30
°
is also described by Eq. 833.
With
Δ
E
th
again equal to 26 J, we have
KU
f
d
m
g
ym
v
k
top
top
bot
bot
bot
+=++
¡
+
+
0
1
2
02
6
2
from which we find
v
bot
ms
=
21
.
.
106. We take the bottom of the incline to be the
y
= 0 reference level. The incline angle is
30
=°
. The distance along the incline
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Conservation Of Energy, Energy

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