ch08-p106

# ch08-p106 - 106. We take the bottom of the incline to be...

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KU K U f d mv mgy f d mv mgd mgd k k k 00 0 2 0 2 1 2 1 2 += + + +=+ + =+ top top sin cos θμ θ which — upon canceling the mass and rearranging — provides the result for d : d v g k = + = 0 2 2 15 μθ cos sin . bg m. (c) The thermal energy generated by friction is f k d = μ k mgd cos = 26 J. (d) The slide back down, from the height y = 1.5 sin 30 ° is also described by Eq. 8-33. With Δ E th again equal to 26 J, we have KU f d m g ym v k top top bot bot bot +=++ ¡ + + 0 1 2 02 6 2 from which we find v bot ms = 21 . . 106. We take the bottom of the incline to be the y = 0 reference level. The incline angle is 30 . The distance along the incline
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## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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