ch08-p107 - 107. (a) The effect of a (sliding) friction is...

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Kk d k d d f d k =− + 1 2 2 0 bg . In this first approach, we could work through the dK dd = 0 condition (or with the special capabilities of a graphing calculator) to obtain the answer K k kd f k max 1 2 0 2 . In the second (and perhaps easier) approach, we note that K is maximum where v is maximum — which is where a = ¡ 0 equilibrium of forces. Thus, the second approach simply solves for the equilibrium position Ff k x k spring = ¡ = 80. Thus, with k = 4000 N/m we obtain x = 0.02 m. But x = d 0 d so this corresponds to d = 0.08 m. Then the methods of part (a) lead to the answer K max = 12.8 J 13 J. 107. (a) The effect of a (sliding) friction is described in terms of energy dissipated as
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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