Note: one might wish to check that the skier stays in contact with the hill — which is indeed the case, here. For instance, at Awe find v2/r≈2 m/s2which is considerably less thang.(b) With KA= 0, we have KUKmgyBBAABA+=+¡00which yields KB= 724 J, and the corresponding speed is vKm==249.ms.(c) Expressed in terms of mass, we have mvmgymvmgyBBAA¡+=+121222.Thus, the mass mcancels, and we observe that solving for speed does not depend on the value of mass (or weight). 110. We take her original elevation to be the
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.