ch08-p110 - 110 We take her original elevation to be the y...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Note: one might wish to check that the skier stays in contact with the hill — which is indeed the case, here. For instance, at A we find v 2 / r 2 m/s 2 which is considerably less than g . (b) With K A = 0, we have KU K m g y BBAA B A +=+ ¡ 00 which yields K B = 724 J, and the corresponding speed is vK m == 24 9 .m s . (c) Expressed in terms of mass, we have mv mgy mv mgy BB AA ¡ += + 1 2 1 2 22 . Thus, the mass m cancels, and we observe that solving for speed does not depend on the value of mass (or weight). 110. We take her original elevation to be the
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online