119. (a) During the final d= 12 m of motion, we use 112 2210002kkKU KU fdmvf d+=+++=++wherev= 4.2 m/s. This gives fk= 0.31 N. Therefore, the thermal energy change is 3.7 J.kfd=(b) Using fk= 0.31 N we obtain fkdtotal= 4.3 J for the thermal energy generated by friction; here,dtotal= 14 m. (c) During the initial
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.