ch08-p119 - 119. (a) During the final d = 12 m of motion,...

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119. (a) During the final d = 12 m of motion, we use 11 2 2 2 1 000 2 k k KU KU f d mv f d += ++ +=++ where v = 4.2 m/s. This gives f k = 0.31 N. Therefore, the thermal energy change is 3.7 J. k fd = (b) Using f k = 0.31 N we obtain f k d total = 4.3 J for the thermal energy generated by friction; here, d total = 14 m. (c) During the initial
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