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119. (a) During the final
d
= 12 m of motion, we use
11
2 2
2
1
000
2
k
k
KU KU f
d
mv
f d
+=
++
+=++
where
v
= 4.2 m/s. This gives
f
k
= 0.31 N. Therefore, the thermal energy change is
3.7 J.
k
fd
=
(b) Using
f
k
= 0.31 N we obtain
f
k
d
total
= 4.3 J for the thermal energy generated by friction;
here,
d
total
= 14 m.
(c) During the initial
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 Spring '08
 Any
 Physics, Energy, Thermal Energy

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