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Unformatted text preview: . 123. Converting to SI units, v0 = 8.3 m s and v = 111 m s . The incline angle is θ = 5.0° . The height difference between the car's highest and lowest points is (50 m) sin θ = 4.4 m. We take the lowest point (the car's final reported location) to correspond to the y = 0 reference level. (a) Using Eq. 8-31 and Eq. 8-33, we find
f k d = − ΔK − ΔU fkd = 1 2 m v0 − v 2 + mgy0 . 2 c h Therefore, the mechanical energy reduction (due to friction) is fk d = 2.4 × 104 J. (b) With d = 50 m, we solve for fk and obtain 4.7 × 102 N. ...
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
- Spring '08