128. The distance traveled up the incline can be figured with Chapter 2 techniques:vvaxx2022200=+→=ΔΔm. This corresponds to an increase in height equal to y= (200 m) sin θ= 17 m, where5.0=°. We take its initial height to be y= 0. (a) Eq. 8-24 leads to WEmvvmgyapp==−+Δ12202ch.Therefore,ΔE=×86 103.J.(b) From the above manipulation, we see Wapp= 8.6 ×103J. Also, from Chapter 2, we know that tva10 s. Thus, using Eq. 7-42, PWtavgW×=Δ108603.where the answer has been rounded off (from the 856 value that is provided by the calculator).
This is the end of the preview. Sign up
access the rest of the document.