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128. The distance traveled up the incline can be figured with Chapter 2
techniques:
vv
a
x
x
2
0
2
2
200
=+
→
=
ΔΔ
m. This corresponds to an increase in height
equal to
y
= (200 m) sin
θ
= 17 m, where
5.0
=°
. We take its initial height to be
y
= 0.
(a) Eq. 824 leads to
WE
m
v
v
m
g
y
app
==
−
+
Δ
1
2
2
0
2
c
h
.
Therefore,
Δ
E
=×
86 10
3
.J
.
(b) From the above manipulation, we see
W
app
= 8.6
×
10
3
J. Also, from Chapter 2, we
know that
tv
a
10 s. Thus, using Eq. 742,
P
W
t
avg
W
×
=
Δ
10
860
3
.
where the answer has been rounded off (from the 856 value that is provided by the
calculator).
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 Spring '08
 Any
 Physics

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