for the mass of rainwater. One-third of this “falls” to the ocean, so it is m= 2 ×1015kg that we want to use in computing the gravitational potential energy mgh(which will turn into electrical energy during the year). Since a year is equivalent to 3.2 ×107s, we obtain PavgW.=××=×2 109 8 50032 1031 1015711chbgb g...129. We want to convert (at least in theory) the water that falls through
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.