Ch09-p011 - 11 We use the constant-acceleration equations of Table 2-1(with y downward and the origin at the release point Eq 9-5 for ycom and Eq

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y my mm com m = + + = + + = 11 2 2 12 044 2 020 2 028 .. bg (b) The speed of the first stone at time t is v 1 = gt , while that of the second stone is v 2 = g ( t – 100 × 10 –3 s). Thus, the center-of-mass speed at t = 300 × 10 –3 s is () ( ) ( ) 23 3 com 1 1 9.8 m/s 300 10 s 2 9.8 m/s 300 10 s 100 10 s 2 2.3 m/s. mv v m m −− ×+ × × + == ++ = 11. We use the constant-acceleration equations of Table 2-1 (with + y downward and the origin at the release point), Eq. 9-5 for y com and Eq. 9-17 for G v com . (a) The location of the first stone (of mass
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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