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14. (a) The phrase (in the problem statement) “such that it [particle 2] always stays
directly above particle 1 during the flight” means that the shadow (as if a light were
directly above the particles shining down on them) of particle 2 coincides with the
position of particle 1, at each moment.
We say, in this case, that they are vertically
aligned.
Because of that alignment,
v
2x
=
v
1
= 10.0 m/s.
Because the initial value of
v
2
is
given as 20.0 m/s, then (using the Pythagorean theorem) we must have
22
2
yx
vv
v
=−
=
300
m/s
for the initial value of the
y
component of particle 2’s velocity. Eq. 216 (or conservation
of energy) readily yields
y
max
= 300/19.6 = 15.3 m.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Light

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