14. (a) The phrase (in the problem statement) “such that it [particle 2] always stays directly above particle 1 during the flight” means that the shadow (as if a light were directly above the particles shining down on them) of particle 2 coincides with the position of particle 1, at each moment. We say, in this case, that they are vertically aligned. Because of that alignment, v2x= v1= 10.0 m/s. Because the initial value of v2is given as 20.0 m/s, then (using the Pythagorean theorem) we must have 222yxvvv=−=300 m/s for the initial value of the ycomponent of particle 2’s velocity. Eq. 2-16 (or conservation of energy) readily yields ymax= 300/19.6 = 15.3 m.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.