ch09-p017 - 17. There is no net horizontal force on the...

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. d bd b m x x m Δ= Δ Now we express the geometrical condition that relative to the boat the dog has moved a distance d = 2.4 m: ΔΔ xx d += which accounts for the fact that the dog moves one way and the boat moves the other. We substitute for | Δ x b | from above: m m d d b dd b g which leads to 2.4 m 1.92 m. 1 / 1 (4.5/18) d db d x mm Δ= = = ++ The dog is therefore 1.9 m closer to the shore than initially (where it was
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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