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.
d
bd
b
m
x
x
m
Δ= Δ
Now we express the geometrical condition that
relative to the boat
the dog has moved a
distance
d
= 2.4 m:
ΔΔ
xx
d
+=
which accounts for the fact that the dog moves one way and the boat moves the other. We
substitute for 
Δ
x
b
 from above:
m
m
d
d
b
dd
b
g
which leads to
2.4 m
1.92 m.
1
/
1 (4.5/18)
d
db
d
x
mm
Δ=
=
=
++
The dog is therefore 1.9 m closer to the shore than initially (where it was
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Center Of Mass, Force, Mass

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