wheremis the mass, vithe initial velocity, and vfthe final velocity of the ball. Thus, ()()3avg0.40kg 14m s1200 N 27 10 s67m s.0.40kgifmvFtvm−−×−Δ===−(a) The final speed of the ball is ||fv=67 m/s.(b) The negative sign indicates that the velocity is in the –xdirection, which is opposite to the initial direction of travel. (c) From the above, the average magnitude of the force is 3avg1.20 10 NF=×.(d) The direction of the impulse on the ball is –
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