ch09-p024 - 24(a By energy conservation the speed of the...

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24. (a) By energy conservation, the speed of the victim when he falls to the floor is 22 1 2 2(9.8 m/s )(0.50 m) 3.1m/s. 2 mv mgh v gh = ¡ == = Thus, the magnitude of the impulse is 2 | | | | (70 kg)(3.1m/s) 2.2 10 N s.
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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