Ch09-p035 - 35(a We take the force to be in the positive direction at least for earlier times Then the impulse is J= 3.0 10 3 0 Fdt = 3.0 10 3

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F max 69 3 6.0 10 10 2.0 10 10 4.5 10 N. × −× × = × −− ch 15 33 2 .. (d) Since it starts from rest, the ball acquires momentum equal to the impulse from the kick. Let m be the mass of the ball and v its speed as it leaves the foot. Then, 9.0 N s 20 m/s. 0.45 kg pJ v mm === = 35. (a) We take the force to be in the positive direction, at least for earlier times. Then the impulse is 3 3.0 10 2 00 3.0 62 93 0 (6.0 10 ) (2.0 10 ) 11 23 9.0N s. J Fdt t t dt tt ×× × ªº == × × ¬¼
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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