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(a) Conservation of linear momentum requires
Mv
m v
m v
m v
G
G
G
H
01
12
23
3
=++
, which (using the
above information) leads to
33
3
ˆˆ
(1.00 10 i 0.167 10 j) m/s
v
=×
−
×
G
.
The magnitude of
G
v
3
is
22
3
3
(1000 m/s)
( 167 m/s)
1.01 10 m/s
v
=+
−
=
×
. It points at
θ
=
tan
–1
(–167/1000) = –9.48° (that is, at 9.5° measured clockwise from the +
x
axis).
(b) We are asked to calculate
Δ
K
or
1
2
1
2
1
2
1
2
323 10
11
2
2
2
0
26
mv
Mv
++
F
H
G
I
K
J
−=
×
.J
.
47. Our notation is as follows: the mass of the original body is
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Mass

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