ch09-p056 - We can use Ch. 2 methods or energy methods to...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
56. The total momentum immediately before the collision (with + x upward) is p i = (3.0 kg)(20 m/s) + (2.0 kg)( –12 m/s) = 36 kg·m/s. Their momentum immediately after, when they constitute a combined mass of M = 5.0 kg, is p f = (5.0 kg) v G . By conservation of momentum, then, we obtain v G = 7.2 m/s, which becomes their "initial" velocity for their subsequent free-fall motion.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: We can use Ch. 2 methods or energy methods to analyze this subsequent motion; we choose the latter. The level of their collision provides the reference ( y = 0) position for the gravitational potential energy, and we obtain K + U = K + U 1 2 Mv 2 + 0 = 0 + Mgy max . Thus, with v = 7.2 m/s, we find y max = 2.6 m....
View Full Document

This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online