ch09-p056

# ch09-p056 - We can use Ch. 2 methods or energy methods to...

This preview shows page 1. Sign up to view the full content.

56. The total momentum immediately before the collision (with + x upward) is p i = (3.0 kg)(20 m/s) + (2.0 kg)( –12 m/s) = 36 kg·m/s. Their momentum immediately after, when they constitute a combined mass of M = 5.0 kg, is p f = (5.0 kg) v G . By conservation of momentum, then, we obtain v G = 7.2 m/s, which becomes their "initial" velocity for their subsequent free-fall motion.
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: We can use Ch. 2 methods or energy methods to analyze this subsequent motion; we choose the latter. The level of their collision provides the reference ( y = 0) position for the gravitational potential energy, and we obtain K + U = K + U 1 2 Mv 2 + 0 = 0 + Mgy max . Thus, with v = 7.2 m/s, we find y max = 2.6 m....
View Full Document

## This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online