ch09-p057 - 57. We choose +x in the direction of (initial)...

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( ) ( ) () ( ) ( ) 11 2 2 1 5 kg 3.0 m/s 10 kg 2.0 m/s (5 kg) 10 kg 2.5 m/s iif f f mv v +=+ += + GGG G G which yields 1 2.0 m/s f v = G . Thus, the speed of the 5.0 kg block immediately after the collision is 20 .ms . (b) We find the reduction in total kinetic energy: ( ) ( ) ( ) 22 2 2 5 kg 3 m/s 10 kg 2 m/s 5 kg 2 m/s 10 kg 2.5 m/s 1.25 J 1.3 J. if KK −= + =− ≈− (c) In this new scenario where G v f 2 40 = . m s , momentum conservation leads to G v f 1 10 . m s and we obtain 40 J K Δ= + . (d) The creation of additional kinetic energy is possible if, say, some gunpowder were on
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