62. (a) Let mAbe the mass of the block on the left, vAibe its initial velocity, and vAfbe its final velocity. Let mBbe the mass of the block on the right, vBibe its initial velocity, and vBfbe its final velocity. The momentum of the two-block system is conserved, so mAvAi+mBvBi= mAvAf+ mBvBfand(1.6 kg)(5.5m/s) (2.4 kg)(2.5m/s) (2.4 kg)(4.9 m/s)1.6kg1.9 m/s.AAiBBifAfAmvvm+−===(b) The block continues going to the right after the collision. (c) To see if the collision is elastic, we compare the total kinetic energy before the
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