We solve for m2to obtain mvvmiffi2111=−+.We combine this with 4=/ to obtain ()21353 2.0 kg 5 1.2 kgmm===.(b) The speed of the center of mass is ()2 2com122.0 kg 4.0 m/s2.5 m s2.0 kg 1.2 kgiimvv+=++.63. (a) Let m1be the mass of the body that is originally moving, v1ibe its velocity before the collision, and
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.