This preview shows page 1. Sign up to view the full content.
Unformatted text preview: collision (at x = 0 and t = 0): v 1 f = m 1 m 2 m 1 + m 2 v 1 i = 0.1 kg 0.7 kg (2.0 m/s) = 2 7 m/s v 2 f = 2 m 1 m 1 + m 2 v 1 i = 0.6 kg 0.7 kg (2.0 m/s) = 12 7 m/s 1.7 m/s. At a rate of motion of 1.7 m/s, 2 x w = 140 cm (the distance to the wall and back to x = 0) will be traversed by particle 2 in 0.82 s. At t = 0.82 s, particle 1 is located at x = (2/7)(0.82) = 23 cm,...
View
Full
Document
This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details