ch09-p069 - 69. (a) We use conservation of mechanical...

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69. (a) We use conservation of mechanical energy to find the speed of either ball after it has fallen a distance h . The initial kinetic energy is zero, the initial gravitational potential energy is M gh , the final kinetic energy is 1 2 2 Mv , and the final potential energy is zero. Thus Mgh Mv = 1 2 2 and vg h = 2. The collision of the ball of M with the floor is an elastic collision of a light object with a stationary massive object. The velocity of the light object reverses direction without change in magnitude. After the collision, the ball is traveling upward with a speed of 2 gh . The ball of mass m is traveling downward with the same speed. We use Eq. 9-75 to find an expression for the velocity of the ball of mass M after the collision: 22 3 2 . Mf
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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