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71. We orient our +
x
axis along the initial direction of motion, and specify angles in the
“standard” way — so
θ
= +60° for the proton (1) which is assumed to scatter into the first
quadrant and
φ
= –30° for the target proton (2) which scatters into the fourth quadrant
(recall that the problem has told us that this is perpendicular to
). We apply the
conservation of linear momentum to the
x
and
y
axes respectively.
mv
11
1 1
2 2
0
=+
' cos
' cos
's
in
θφ
We are given
v
1
= 500 m/s, which provides us with two unknowns and two equations,
which is sufficient for solving. Since
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 Spring '08
 Any
 Physics

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