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m
R
v
R
+
m
L
v
L
= 0
¡
(0.500 kg)
v
R
+ (1.00 kg)(
−
1.20 m/s)
=
0
which yields
v
R
= 2.40 m/s. Thus,
Δ
x
=
v
R
t
= (2.40 m/s)(0.800 s) = 1.92 m.
(b) Now we have
m
R
v
R
+
m
L
(
v
R
−
1.20 m/s)
=
0, which yields
(1.2 m/s)
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This note was uploaded on 05/17/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Momentum

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